Tuesday, April 1, 2014

Heat of Fusion for Ice

Purpose:

Procedure:
1) Start with 100 ml H2O at fifty degrees Celsius
2) Place H2O into calorimeter and record temperature
3) Drop two to three ice cubes into calorimeter and stir until temperature no longer drops. Remove any remaining ice (don't run out of ice!)
4) Measure new volume

Data:
Temperature of H2O in calorimeter: 50 degrees Celsius
Volume of H2O after melting ice cubes: 163 ml

Calculations:
1) Mass of H2O used: 100 ml=100 g
2) Heat given by water: 100g x -48.7 x 4.18= -20,356.6 joules
3) Heat taken by ice: 20,356.6 joules
4) Mass of ice: 63g
5) Moles of Melted ice: 63g---> 3.5 moles
6) Heat Fusion: 20.4 kJ/3.5 mol ----> 5.8 kJ

Conclusion:

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